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  3. 2018年11月网络工程师考试上午真题【基础知识】
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2018年11月网络工程师考试上午真题【基础知识】

【61】下列命令中,不能用于诊断DNS故障的是(61)

真题详情及解析

【62】在冗余磁盘阵列中,以下不具有容错技术的是(62)

真题详情及解析

【63】下面的描述中属于工作区子系统区城范围的是(63)

真题详情及解析

【64】以下关于三层交换机的叙述中,正确的是(64)

真题详情及解析

【65】IP数据报首部中IHL(Internet首部长度)字段的最小值(65)

真题详情及解析

【66-67】查看OSPF接口的开销、状态、类型、优先级等的命令是(66);查看OSPF在接收报文时出错记录的命令是(67)

真题详情及解析

【68-69】如图所示,SwitchA通过SwitchB和NMS跨网段相连并正常通信。SwitchA与SwitchB配置相似,从给出的SwitchA的配置文件可知该配置实现的是(68),验证配置结果的命令是(69)

SwitchA 的配置文件
sysname SwitchA
vlan batch 10
bfd
interface Vlanif10
ip address 10.1.1.1 255.255.255.0
interface GigabitEthernet0/0/1
port link-type trunk
port trunk allow-pass vlan 10
bfd aa bind peer-ip 10.1.1.2
discriminator local 10
discriminator remote 20
commit
ip route-static 10.2.2.0 255.255.255.0 10.1.1.2 track bfd-session aa
return

真题详情及解析

【70】如下图所示,使用基本ACL限制FTP访间权限,从给出的Switch的配置文件判断可以实现的策略是(70)

①PC1在任何时间都可以访问FTP
②PC2在2018年的周一不能访问FTP
③PC2在2018年的周六下午3点可以访问FTP
④PC3在任何时间不能访问FTP
Switch 的配置文件
sysname Switch
FTP server enable
FTP acl2001
time-range ftp-access 14:00 to 18:00 off-day
time-range ftp-access from 00:00 2018/1/1 to 23:59 2018/12/31
acl number 2001
rule 5 permit source 172.16.105.0 0.0.0.255
rule 10 permit source 172.16.107.0 0.0.0.255 time-range ftp-access
rule 15 deny
aaa
local-user huawei password irreversible-cipher
local-user huawei privilege level 15
local-user huawei ftp-directory flash:
local-user huawei service-type ftp
return

真题详情及解析

【71-75】The TTL field was originally designed to hold a time stamp, which was decremented by each visited router. The datagram was (71) when the value became zero. However, for this scheme, all the machines must have synchronized clocks and must know how long it takes for a datagram to go from one machine to another. Today, this field is used mostly to control the (72) number of hops (routers) visited by the datagram. When a source host sends the datagram, it (73) a number in this field Each router that processes the datagram decrements this number by 1. If this value, after being decremented, is zero,the router discards the datagram.This field is needed because routing tables in the Internet can become corrupted. A datagram may travel between two or more routers for a long time without ever getting delivered to the(74).This field limits the (75) of a datagram.

真题详情及解析
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